Beam Calculator: Deflection, Shear and Moment

Calculate beam reactions, shear and moment diagrams, deflection and bending stress for common supports, combined loads, and steel or timber sections.

#beam #bending stress #deflection #Euler–Bernoulli #shear and moment diagrams #steel #timber

This beam calculator finds support reactions, shear force, bending moment, elastic deflection and bending stress for a straight beam. Engineers can use it to compare sections or investigate a machine frame; students can use it to follow equilibrium and integration; makers can explore the effect of span, board orientation and load position.

Choose a pin-and-roller beam, a cantilever fixed at the left end, a beam fixed at both ends, or a propped cantilever. Enter the beam length and cross-section. The section choices include IPE profiles, a solid rectangle or circle, rectangular and circular tubes, a dressed 2x4, and directly entered section properties. The depth is vertical in the bending plane. Turning a board flat changes its stiffness substantially, even though its area stays the same.

Select a metal preset, an illustrative timber species, or your own Young's modulus and density. The timber presets are average clear-wood properties at 12% moisture content, not grade-specific structural design values. A nominal 2x4 uses actual dimensions of 1.5 by 3.5 inches. Measure your member and use the rectangle option when its dimensions differ.

Enter up to two point loads and one uniform distributed load. The distributed load may cover the whole beam or a selected interval. Positive loads act downward and negative loads upward; set a load to zero to omit it. Load positions are measured from the left end. Add self-weight only if it is absent from the loads you entered. Use the unit selector to work in metric or US customary units without changing the physical case.

The beam drawing shows the supports, active loads and an exaggerated deflected shape. As a shear and moment diagram calculator, the tool preserves the jumps at point loads and identifies the largest absolute internal actions. The beam deflection calculator reports the largest displacement and its position, which may be away from midspan. Move the inspection position to read local shear, moment, deflection and rotation. At a point load, inspection shear is taken just to its right; at the right end, it is taken from inside the beam.

Results assume a constant section and stiffness, linear elasticity, ideal supports and small deformation. Positive moment means sagging; plotted deflection is positive downward. Support forces are positive upward, and support couples are positive counterclockwise. An upward load can require hold-down at a bearing.

Bending stress is an elastic stress estimate, not a load capacity or a pass/fail verdict. This tool does not perform Eurocode, AWC or other building-code checks. It excludes buckling, bearing, connections, torsion, shear deformation, timber creep, vibration, impact and load combinations. Use a suitable structural analysis and qualified engineering judgement when those effects govern.

How it is calculated

The solver is derived here from equilibrium and the Euler–Bernoulli relation EIy′′=MEIy''=M, with yy positive upward. It follows the Macaulay bracket and superposition approach illustrated by D. J. Dunn, Deflection of Beams, pp.11–15, and the statics relationships on FIRGELLI's beam page.

For ⟨x−a⟩n\langle x-a\rangle^n, negative arguments contribute zero; order zero is a right-continuous unit step. Let Jn(x)J_n(x) be the sum of the point-load terms P⟨x−a⟩n/n!P\langle x-a\rangle^n/n!, the patch-load term q[⟨x−s⟩n+1−⟨x−e⟩n+1]/(n+1)!q[\langle x-s\rangle^{n+1}-\langle x-e\rangle^{n+1}]/(n+1)!, and the self-weight term qswxn+1/(n+1)!q_{sw}x^{n+1}/(n+1)!.

V=RA−J0,M=M0+RAx−J1V=R_A-J_0,\qquad M=M_0+R_Ax-J_1
EIy′=M0x+RAx2/2−J2+C1EIy'=M_0x+R_Ax^2/2-J_2+C_1
EIy=M0x2/2+RAx3/6−J3+C1x.EIy=M_0x^2/2+R_Ax^3/6-J_3+C_1x.

For pin + roller, impose M(0)=M(L)=y(0)=y(L)=0M(0)=M(L)=y(0)=y(L)=0. For a cantilever impose y(0)=y′(0)=0y(0)=y'(0)=0 and free-end equilibrium including any tip load. For fixed ends impose y=y′=0y=y'=0 at both ends. For the propped cantilever impose y(0)=y′(0)=y(L)=M(L)=0y(0)=y'(0)=y(L)=M(L)=0. These conditions give the readable reaction and integration-constant steps.

The span is split at load discontinuities. Exact polynomial roots of V=0V=0 and y′=0y'=0, together with every interval end, locate the absolute moment and deflection peaks. Charts use 41 points per nonzero interval; duplicated positions retain the two shear limits at point loads. The peak results do not depend on this plotting grid.

Section formulas are I=bh3/12I=bh^3/12 for a rectangle and I=πD4/64I=\pi D^4/64 for a solid circle, subtracting the inner shape for tubes. IPE properties come from the platform catalog including root fillets. Stress is σb=∣M∣maxcmax/I\sigma_b=|M|_{max}c_{max}/I. Self-weight is qsw=ρAgq_{sw}=\rho A g when selected.

Assumptions

  • Straight, prismatic, homogeneous beam with constant EIEI and loads in one bending plane. No applied concentrated couples or axial force.
  • Ideal supports prevent the selected translations and rotations, with no settlement or support flexibility. A bearing requiring a negative reaction needs a hold-down.
  • Small rotations, linear elasticity and plane sections remaining plane. Shear deformation and geometric stiffness are omitted.
  • The rectangle's entered depth is vertical. IPE strong/weak axes and the dressed 2x4 orientation can be switched. Tubes have ideal sharp corners.
  • Custom section stress uses the entered farthest fibre distance; the outline depth is represented as 2cmax2c_{max} only for reporting.
  • Metal properties are platform reference-table values. Timber moduli and air-dry shipping densities come from Oregon State's table; these are illustrative clear-wood averages, not allowable stresses or graded-lumber stiffness guarantees.
  • The equations and support-condition solution are derived here; the named publications supply independent checks. The diagram separates load arrows into lanes above the beam and shows the exaggerated deflection on a separate baseline below it, so upward deflection stays clear of load labels.

Where it applies

Use for elastic bending estimates and teaching. The warning at length/depth < 10 is a prompt to assess shear deformation, not a universal accuracy limit. A displacement over 2% of beam length triggers a small-deflection warning; the actual acceptable limit depends on the application.

No Eurocode, AWC, AISC or other code compliance, strength capacity or safe-load claim is made. No yield, shear, local or lateral-torsional buckling, fatigue, torsion, bearing, connection, stability, creep, vibration, dynamic amplification, load factors or combinations are checked. Timber grading, moisture, duration of load and long-term deformation need a separate assessment. IPE dimensions follow the platform's EN 10365:2017-based catalog; this does not make the calculation a code check. Check against the standard in force when using catalog data for a project.

The inspection shear is the right-hand value at an internal point load and the left-hand value at the right end. Equal absolute peaks report the first position found. Signed deflection can be upward or downward; the maximum card is always a magnitude. Equilibrium residuals retain floating-point roundoff; the normalized right-end displacement residual is rounded to 12 decimal places.

References

  • D. J. Dunn, Deflection of Beams, worked examples 2, 5 and 6; Macaulay method and superposition, pp.6, 11–14. https://www.freestudy.co.uk/CG130/3t1.pdf
  • FIRGELLI, Shear Force and Bending Moment Diagram Generator: statics relationships and simply supported examples. https://www.firgelliauto.com/blogs/engineering-calculators/shear-force-and-bending-moment-diagram-generator
  • University of Bolton, CIE5016, 9 January 2024, Table Q1, p.3: fixed-end moments and propped-cantilever reactions. https://hub.bolton.ac.uk/Quality/EEE/Examination-Papers/Documents/2023-24-Sem1/A-E/RAK-CIE5016.pdf
  • Oregon State University, Oregon Wood Innovation Center: Physical Properties table, timber bending moduli at 12% moisture and air-dry shipping weights. https://owic.oregonstate.edu/table-relative-working-and-physical-properties-inch-pound
  • NIST, Making Sure that Lumber Measures Up, 1 March 2017: nominal 2x4 actual dimensions. https://www.nist.gov/news-events/news/2017/03/making-sure-lumber-measures
  • Platform reference tables materials.metals and steel.ipe: elastic modulus, density and IPE section properties. ArcelorMittal European sections catalog: https://sections.arcelormittal.com/

Inputs

InputSymbolUnitDefault
SupportssupportPin + roller
Beam lengthLm6
Cross-sectionshapeIPE steel section
IPE sectionsectionIPE 240
Bending orientationaxisStrong axis / board on edge
Section widthb_inmm100
Vertical section depthh_inmm200
Outside diameterD_inmm100
Tube wall thickness
Ideal sharp corners; use catalog properties for manufactured tubes.
t_inmm5
Section areaA_incm^2100
Second moment about bending axisI_incm^410000
Farthest fibre from neutral axis
Use the larger top/bottom distance. Shear centre and torsion are not modelled.
c_inmm100
Materialmaterial_modeMetal preset
MetalmetalCarbon steel
Timber species at 12% moisture
Average small clear specimens, not graded structural lumber design values. Use a verified grade-specific modulus for a real member.
woodDouglas-fir (clear wood)
Young's modulusE_inGPa200
Mass densityrho_inkg/m^37850
Point load 1
Positive downward; negative upward. Set to zero to omit.
P_1kN10
Point load 1 from left enda_1m2
Point load 2
Positive downward; negative upward. Set to zero to omit.
P_2kN0
Point load 2 from left enda_2m4
Distributed load intensity
Uniform over the full beam or the selected loaded interval. Positive downward.
qkN/m5
Distributed load covers the full beamfull_spantrue
Distributed load starts from lefts_inm0
Distributed load ends from lefte_inm6
Add beam self-weight
Adds density × section area × standard gravity over the full beam; avoid double counting.
self_weightfalse
Inspect at fraction of beam length
0 = left end, 0.5 = middle, 1 = right end.
probe0.5

Results

With the default inputs above, the calc gives:

ResultValue
Maximum absolute deflection15.028 mm
Maximum elastic bending stress103.63 MPa
Maximum absolute bending moment33.611 kN·m
Maximum absolute shear force21.667 kN
Left reaction · upward positive21.667 kN
Right reaction · upward positive18.333 kN
Deflection peak from left end2.915 m
Moment peak from left end2.333 m

Checked against sources

Each case below was calculated by this calc and agrees with the value from its source (within the tolerance where one is shown).

FIRGELLI: 6 m, 10 kN at 2 m + 5 kN/m

Source: FIRGELLI, Worked Example: Simply Supported Beam, reactions rounded to 2 decimals. https://www.firgelliauto.com/blogs/engineering-calculators/shear-force-and-bending-moment-diagram-generator

Inputs: the default inputs above.

ResultSourceThis calc
Left reaction · upward positive21.67 kN21.667 kN
Right reaction · upward positive18.33 kN18.333 kN

FIRGELLI: 50 kN at centre of a 10 m beam

Source: FIRGELLI, Simple Example, 10 m span with 50 kN at 5 m; published maximum bending moment 125 kN·m. https://www.firgelliauto.com/blogs/engineering-calculators/shear-force-and-bending-moment-diagram-generator

Inputs: Beam length = 10 m; Point load 1 = 50 kN; Point load 1 from left end = 5 m; Distributed load intensity = 0 kN/m; the others as above.

ResultSourceThis calc
Left reaction · upward positive25 kN25 kN
Right reaction · upward positive25 kN25 kN
Maximum absolute bending moment125 kN·m125 kN·m

Dunn example 2: cantilever with UDL

Source: D. J. Dunn, Deflection of Beams, p.6, example 2. EI=60 MN·m² represented by E=200 GPa, I=0.0003 m⁴. The source's cantilever is drawn with its fixed end at the right; this tool mirrors it, preserving deflection and slope magnitudes. https://www.freestudy.co.uk/CG130/3t1.pdf

Inputs: Beam length = 4 m; Supports = Cantilever: fixed at left; Cross-section = Enter section properties; Second moment about bending axis = 30,000 cm⁴; Material = Enter material properties; Point load 1 = 0 kN; Distributed load intensity = 0.3 kN/m; the others as above.

ResultSourceThis calc
Maximum absolute deflection0.16 mm0.16 mm
Magnitude of right-end rotation5.33 × 10⁻⁵ ± 1 × 10⁻⁷ rad5.333 × 10⁻⁵ rad

Dunn example 5: cantilever superposition

Source: D. J. Dunn, Deflection of Beams, p.11, example 5. EI=20 MN·m². Published total deflection truncates to 1.54 mm; exact superposition is 1.5466667 mm, so a 0.01 mm tolerance accommodates the printed rounding. The printed UDL denominator 48EI is a typo: the substitution and result use 8EI. https://www.freestudy.co.uk/CG130/3t1.pdf

Inputs: Beam length = 4 m; Supports = Cantilever: fixed at left; Cross-section = Enter section properties; Material = Enter material properties; Point load 1 = 1 kN; Point load 1 from left end = 4 m; Distributed load intensity = 0.3 kN/m; the others as above.

ResultSourceThis calc
Maximum absolute deflection1.54 ± 0.01 mm1.547 mm
Magnitude of right-end rotation5.6 × 10⁻⁴ rad5.6 × 10⁻⁴ rad

Dunn example 6: two off-centre point loads

Source: D. J. Dunn, Deflection of Beams, pp.13–14, example 6. EI=200 MN·m²; published reactions and middle deflection are rounded. This tool uses unrounded reactions. https://www.freestudy.co.uk/CG130/3t1.pdf

Inputs: Beam length = 7 m; Cross-section = Enter section properties; Second moment about bending axis = 100,000 cm⁴; Material = Enter material properties; Point load 1 = 30 kN; Point load 2 = 40 kN; Point load 2 from left end = 4.5 m; Distributed load intensity = 0 kN/m; the others as above.

ResultSourceThis calc
Left reaction · upward positive35.71 kN35.714 kN
Right reaction · upward positive34.29 kN34.286 kN
Signed deflection at inspection point2.09 ± 0.005 mm2.09 mm

Bolton formula sheet: fixed beam, eccentric point load

Source: University of Bolton, CIE5016 examination 9 January 2024, p.3, Table Q1: fixed-end moment magnitudes Pab²/L² and Pa²b/L². Evaluated independently for P=27 kN, L=6 m, a=2 m, b=4 m; reactions follow overall statics. Source uses member-end moment sign notation; this tool's external support couples are counterclockwise positive. https://hub.bolton.ac.uk/Quality/EEE/Examination-Papers/Documents/2023-24-Sem1/A-E/RAK-CIE5016.pdf

Inputs: Supports = Fixed at both ends; Point load 1 = 27 kN; Distributed load intensity = 0 kN/m; the others as above.

ResultSourceThis calc
Left support couple (positive counterclockwise)24 kN·m24 kN·m
Right support couple (positive counterclockwise)-12 kN·m-12 kN·m
Left reaction · upward positive20 kN20 kN
Right reaction · upward positive7 kN7 kN
Maximum absolute bending moment24 kN·m24 kN·m

Bolton formula sheet: propped cantilever, uniform load

Source: University of Bolton, CIE5016 examination 9 January 2024, p.3, Table Q1: propped-cantilever UDL reactions 5wL/8 and 3wL/8, fixing moment magnitude wL²/8; independently evaluated for w=2 kN/m, L=4 m. https://hub.bolton.ac.uk/Quality/EEE/Examination-Papers/Documents/2023-24-Sem1/A-E/RAK-CIE5016.pdf

Inputs: Supports = Fixed left + roller right; Beam length = 4 m; Point load 1 = 0 kN; Distributed load intensity = 2 kN/m; the others as above.

ResultSourceThis calc
Left reaction · upward positive5 kN5 kN
Right reaction · upward positive3 kN3 kN
Left support couple (positive counterclockwise)4 kN·m4 kN·m
Right support couple (positive counterclockwise)0 kN·m0 kN·m

Bolton formula sheet: propped cantilever, midpoint load

Source: University of Bolton, CIE5016 examination 9 January 2024, p.3, Table Q1: midpoint-load reactions 11P/16 and 5P/16, fixing moment magnitude 3PL/16; independently evaluated for P=16 kN and L=4 m. https://hub.bolton.ac.uk/Quality/EEE/Examination-Papers/Documents/2023-24-Sem1/A-E/RAK-CIE5016.pdf

Inputs: Supports = Fixed left + roller right; Beam length = 4 m; Point load 1 = 16 kN; Distributed load intensity = 0 kN/m; the others as above.

ResultSourceThis calc
Left reaction · upward positive11 kN11 kN
Right reaction · upward positive5 kN5 kN
Left support couple (positive counterclockwise)12 kN·m12 kN·m

Dunn fixed-end UDL formulas: deflection and rectangular-section stress

Source: D. J. Dunn, Deflection of Beams, p.20: fixed-end UDL closed forms independently evaluated for q=2 kN/m, L=4 m, E=200 GPa and a 100×200 mm rectangle. Delta=qL^4/(384EI)=0.1 mm, end |M|=qL²/12=8/3 kN·m; I=bh³/12 and sigma=Mc/I give 4 MPa. https://www.freestudy.co.uk/CG130/3t1.pdf

Inputs: Supports = Fixed at both ends; Beam length = 4 m; Cross-section = Solid rectangle; Material = Enter material properties; Point load 1 = 0 kN; Distributed load intensity = 2 kN/m; the others as above.

ResultSourceThis calc
Maximum absolute deflection0.1 mm0.1 mm
Maximum absolute bending moment2.667 kN·m2.667 kN·m
Left reaction · upward positive4 kN4 kN
Right reaction · upward positive4 kN4 kN
Maximum elastic bending stress4 MPa4 MPa

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