Column Buckling Calculator: Euler, Johnson & Effective Length
Calculate Euler buckling load, Johnson intermediate-column strength and effective length for four end conditions. Explore steel, aluminium and timber presets, eccentric loading and animated buckling modes.
This column buckling calculator estimates when a straight, prismatic member under compression becomes unstable. Engineers and students can compare the Euler buckling load with the Johnson parabola, see how end restraint changes the effective length, and explore an optional eccentric-load calculation.
Choose a US wide-flange section from the AISC property database, enter a rectangle or circular section, or supply area, second moment of area and extreme-fibre distance for one checked axis. Select the material, unbraced length and ideal supports. The weak axis is the starting choice because it usually governs when the lateral restraints are the same in both directions. Use the metric/US switch to enter familiar dimensions and loads; the calculator converts them before evaluating the equations.
The effective length factor is 1 for pinned–pinned ends, about 0.699 for fixed–pinned ends, 0.5 for fixed–fixed ends and 2 for a cantilever with one free end. These are ideal values. A welded connection does not automatically provide perfect fixity, and bracing can differ between the two principal planes. The comparison diagram and table hold the section and physical length constant to show the effect of changing restraint.
For metal columns, the tool calculates slenderness KL/r and the transition sqrt(2π²E/F). Above this transition it selects Euler elastic buckling; below it, it selects the Johnson intermediate-column estimate. Both curves meet at half the entered yield or column strength. The result cards show the selected limiting load, the ideal Euler load, and a screening load obtained by dividing the estimate by your chosen load factor of safety. Applied load divided by screening load is a comparison ratio, not a code compliance certificate.
The aluminium preset uses published extrusion data. The timber preset represents clear, straight-grained Douglas-fir at 12% moisture, loaded parallel to grain. Its estimate is Euler capped by a crushing-strength ceiling; it does not use Johnson. Actual graded timber requires its own design properties, duration and moisture adjustments, creep treatment and column stability rules.
For pinned–pinned ends, select eccentric loading to calculate elastic secant stress and midspan displacement for equal end eccentricities. The limiting estimate then uses the smaller of the concentric estimate and the elastic first-strength-limit load. It is a preliminary screen where yielding or other nonlinear behaviour matters.
Press ▶ beside the load ramp to watch the first elastic buckling mode grow. The drawn amplitude is deliberately enlarged and qualitative; it is not a calculated displacement or postbuckling prediction. Numerical result cards always use the separate applied compression input.
Local plate buckling, torsional and flexural–torsional instability, frame sidesway, imperfections, connections, lateral loads, fire and dynamic effects are outside this model. The AISC section data is geometry, not an AISC 360 design check. Verify structural members using the applicable design method and check against the standard in force.
How it is calculated
For the selected bending plane, , and . The ideal Euler eigenvalue is
For metals, the Johnson–Euler transition and the concentric curve are
The branches are tangent at ; do not take the minimum of an extrapolated Johnson curve and Euler at all slendernesses. See USAF Stress Analysis Manual (1986), §2.3.1.11.4 (attached link s6), and NIOSH/Gearhart (2007), attached s2 p.2. For timber the separate screen is , with its crossing at .
Ideal factors are 1, 0.5 and 2 for pinned–pinned, fixed–fixed and fixed–free ends. Fixed–pinned uses , where solves ; 0.7 is the common rounded value. The four mode shapes are derived here from the uniform Euler–Bernoulli beam-column equation and its end conditions. Their amplitudes are free in the eigenvalue problem. The playing input changes only a qualitative magnification and the drawing, not the engineering capacity calculations.
For pinned ends with equal end eccentricity in one bending plane,
These expressions require . A 52-iteration bisection on finds the first load reaching the strength ceiling. With eccentric loading, the screening limit is the smaller of that elastic load and the concentric column estimate. The chosen safety factor divides the load limit, not the calculated fibre stress. See Jonkoping Applied Mechanics §8.19 and USAF §2.3.1.7.
Steel section properties are six original AISC Shapes Database v16.0 records, transcribed in attached s4 p.1 and converted explicitly from inches. Steel presets use rounded nominal SI values consistent with ANSI/AISC 360-22 and ASTM A992/A36: 200 GPa; 345/250 MPa. McKechnie rev.6 (2023), attached s3 p.1, supplies aluminium compression E=69.7 GPa and minimum tensile proof strength 240 MPa, used as a preliminary strength ceiling. USDA Wood Handbook FPL-GTR-282 (2021), chapter 5, Table 5-3a, printed p.5-7 / chapter PDF p.7, supplies Coast Douglas-fir E=13.4 GPa and crushing strength 49.9 MPa at 12% moisture. The unadjusted mean bending modulus is used as a stiffness approximation.
Assumptions
A straight, homogeneous, constant-section member; axial compression through the centroid for the main model; small bending strains; uniform material properties; idealized restraints in the selected plane; no intermediate lateral loads or self-weight variation. A free end carries an axial dead load. The section is stable against local buckling, and the entered second moment is about a principal axis. Check both planes using their actual unbraced lengths and restraints.
The optional secant case has equal end eccentricities producing single-curvature bending at pinned ends. No initial crookedness is added to the numerical model. The animation uses a small illustrative shape amplitude rather than an imperfection specified for design. The project-material override keeps the selected preset's metal/timber model family.
Timber properties are species means for clear dry wood parallel to grain, not characteristic or allowable strengths. Aluminium tensile proof strength is an approximation to a compression-strength ceiling; confirm the actual product's compression properties. The Johnson material strength parameter must be justified for the product being checked.
Custom sections may be asymmetric about the checked principal axis. The entered c is the compression-side extreme-fibre distance for the selected direction of eccentric bending. Check the opposite bending direction and any tensile stress separately.
Where it applies
This is a mechanics and preliminary sizing tool, not a structural design approval. Johnson is a semi-empirical intermediate-column model; it is not the ANSI/AISC 360 column curve. ANSI/AISC 360-22 Chapter E also requires section classification, applicable instability modes and resistance/allowable-strength factors, which are not implemented. The AISC property database is v16.0 (2023). Reference editions and data were reviewed on 26 October 2026; check against the standard in force.
Real end fixity, frame stability, residual stress, initial crookedness, local buckling, torsion, biaxial bending, connection failure, lateral loads, shear deformation, creep, load duration, moisture, temperature, fire and dynamic effects need separate assessment. A strong-axis result alone cannot establish member capacity. Stocky members need compression and bearing checks.
The elastic secant solution loses validity at or above the Euler load; those result cards are withheld by an input condition. Before that point, large displacement or stress above the proportional limit can invalidate an elastic prediction. The smaller-of-two-loads eccentric screen does not reproduce an inelastic beam-column design curve. The 2% displacement notice is an author-selected prompt for nonlinear review, not a code acceptance criterion.
The published USAF secant trial is rounded and contains a 10590/10950 psi transposition. Its reference case states the discrepancy and uses a rounding tolerance without altering the equations. The bamboo study reference tests the reported dimensionless Johnson tangent only; it is not evidence for the timber preset's design strength.
References
- USAF, Stress Analysis Manual (1986), §2.3.1.3, .7, .9 and .11.4, public reproduction: https://engineeringlibrary.org/reference/simple-column-analysis-air-force-stress-manual
- D. Gearhart / NIOSH (2007), Application of Parametric Column Analysis to Evaluate Eccentric Loading Conditions on Prop Support Performance, p.2: https://stacks.cdc.gov/view/cdc/8552/cdc_8552_DS1.pdf
- Mirza Cenanovic, Jonkoping University, Applied Mechanics §8.19, Buckling and Example 1: https://mechanics.ju.se/SolidMechanics/Buckling.html
- Bahtiar et al. (2021), Experimental Study on Buckling Resistance of Guadua angustifolia column, Engineering Structures 228, 111548, DOI:10.1016/j.engstruct.2020.111548; legal accepted manuscript: https://pure.coventry.ac.uk/ws/portalfiles/portal/43012657/Binder057.pdf
- AISC Shapes Database v16.0 (2023): https://www.aisc.org/aisc/publications/steel-construction-manual/aisc-shapes-database-v160/ ; original workbook university mirror: https://web.ics.purdue.edu/~jhunjhu0/Steel%20Design/aisc-shapes-database-v16.0.xlsx
- ANSI/AISC 360-22, Specification for Structural Steel Buildings, scope and Chapter E context; not implemented as a design resistance: https://www.aisc.org/publications/steel-standards/aisc-360/
- McKechnie Aluminium, 6061 Revision 6 (April 2023), p.1: https://www.mckechnie.co.nz/uploads/PDF/Technical-Specifications/Aluminium-Specifications/6061%20Revision%206.pdf
- USDA Forest Products Laboratory (2021), Wood Handbook, FPL-GTR-282, chapter 5, Table 5-3a and p.5-2: https://research.fs.usda.gov/download/treesearch/62244.pdf
Inputs
| Input | Symbol | Unit | Default |
|---|---|---|---|
| Cross-section Constant cross-section along the unbraced member. | geometry | US W section (AISC database) | |
| Wide-flange section | section | W8X24 | |
| Buckling axis End restraint is assumed to apply in the selected bending plane. | axis | Weak axis (minimum I) | |
| Rectangle width | b | mm | 100 |
| Rectangle depth | h | mm | 150 |
| Outside diameter | D | mm | 60.3 |
| Tube wall thickness | t_wall | mm | 4 |
| Area | A_user | mm^2 | 4567.73 |
| Second moment about checked axis | I_user | mm^4 | 7617035 |
| Centroid to compressive extreme fibre Use the extreme-fibre distance on the side compressed by eccentric bending. For an asymmetric section, select the distance for the bending direction being checked. | c_user | mm | 82.55 |
| Unbraced length Use the distance between lateral restraints in the plane being checked. | L_col | mm | 3000 |
| Ideal end condition Ideal rotational and lateral restraints, not connection labels. Real frames require a justified effective length factor. | ends | Pinned–pinned · K = 1 | |
| Material preset Timber values are means for clear dry wood parallel to grain, not graded-lumber design values. Aluminium uses compressive E and tensile proof strength as an estimate. | material | Steel A992 — nominal | |
| Enter project material properties The selected preset still sets the model family: metal uses Johnson–Euler; timber uses Euler capped by crushing. | override_mat | false | |
| Project elastic modulus | E_user | GPa | 200 |
| Project yield / compressive strength For metal, use compressive yield or a justified column yield stress. Timber uses a crushing-strength ceiling. | F_user | MPa | 345 |
| Applied compression Positive axial compression. Include all loads relevant to the member. | P_load | kN | 150 |
| Chosen load factor of safety Screening load = estimated limit / this factor. This is not an LRFD resistance factor or an AISC allowable load. | FS | 2 | |
| Load application Secant option is available for pinned–pinned supports only. | load_mode | Concentric | |
| Load eccentricity Equal end eccentricity in the selected bending plane; no transverse load. | ecc | mm | 2 |
| Load ramp · illustrative mode Press ▶ to raise the illustrative load from zero to the concentric estimate. Amplified mode amplitude is qualitative; numerical results use Applied compression. | ramp | 0.9 |
Results
With the default inputs above, the calc gives:
| Result | Value |
|---|---|
| Estimated limiting load · selected case | 1,204.2416 kN |
| Screening load · estimate / chosen factor | 602.1208 kN |
| Applied / screening load · limit 1 | 0.249 |
| Ideal Euler buckling load | 1,670.6027 kN |
| Effective slenderness KL/r | 73.4647 |
| Transition slenderness · selected model | 106.9721 |
| Ideal effective length factor K | 1 |
| Effective length KL | 3,000 mm |
| Radius of gyration · checked axis | 40.8359 mm |
| Maximum elastic compressive stress at applied load | 32.839 MPa |
| Secant displacement · zero in concentric mode | 0 mm |
Checked against sources
Each case below was calculated by this calc and agrees with the value from its source (within the tolerance where one is shown).
Published S355 tube · 3.0 m Euler load
Source: Mirza Cenanovic, Jonkoping University, Applied Mechanics §8.19, Example 1, steel strut 60.3 × 4.0 mm, L=3.0 m: Euler Ncr=65 kN, A=707.5 mm², r=19.96 mm (rounded). https://mechanics.ju.se/SolidMechanics/Buckling.html . Checks the elastic load, not the separate Eurocode design resistance.
Inputs: Cross-section = Circular tube; Enter project material properties = yes; Project elastic modulus = 210 GPa; Project yield / compressive strength = 355 MPa; the others as above.
| Result | Source | This calc |
|---|---|---|
| Ideal Euler buckling load | 65 ± 0.5 kN | 64.88 kN |
| Cross-sectional area | 707.5 mm² | 707.5 mm² |
| Radius of gyration · checked axis | 19.96 mm | 19.955 mm |
Published S355 tube · 1.5 m Euler load
Source: Jonkoping University, Applied Mechanics §8.19, Example 1: for L=1.5 m, Euler Ncr=260 kN and squash Npl=251 kN, rounded to kN. The published Eurocode resistance 170 kN is a different model and is not used as a Johnson target. https://mechanics.ju.se/SolidMechanics/Buckling.html
Inputs: Cross-section = Circular tube; Unbraced length = 1,500 mm; Enter project material properties = yes; Project elastic modulus = 210 GPa; Project yield / compressive strength = 355 MPa; the others as above.
| Result | Source | This calc |
|---|---|---|
| Ideal Euler buckling load | 260 ± 1 kN | 259.5 kN |
| Yield / crushing load | 251,000 ± 500 N | 251,158 N |
Published Johnson–Euler transition · fitted E/strength ratio
Source: Bahtiar et al. (2021), accepted manuscript printed p.20 / attached p.21, equations 41–42 and Figure 15: fitted E/σc=151.2, transition 54.63 at reduction 0.5. Inputs normalize strength to 100 MPa and E to 15120 MPa solely to reproduce that published dimensionless curve. This validates the Johnson tangent numerically; it does not validate a metal material or promote a Johnson timber design rule. DOI:10.1016/j.engstruct.2020.111548
Inputs: Cross-section = Enter A, I and c (one axis); Area = 1,000 mm²; Second moment about checked axis = 100,000 mm⁴; Centroid to compressive extreme fibre = 20 mm; Unbraced length = 546.3 mm; Enter project material properties = yes; Project elastic modulus = 15.12 GPa; Project yield / compressive strength = 100 MPa; the others as above.
| Result | Source | This calc |
|---|---|---|
| Johnson–Euler tangent slenderness | 54.63 | 54.631 |
| Selected critical stress / strength ceiling | 0.5 | 0.5 |
USAF round-column secant trial · rounded published result
Source: USAF Stress Analysis Manual (1986), §2.3.1.9: D=1.215 in, L=50 in, E=30e6 psi, ec/r²=0.25, factored trial load 1.5×5000=7500 lbf, limiting fibre stress 10950 psi. Treat F_0 as that imposed fibre ceiling for this solver check. Exact geometry gives 11032 psi at the trial load and a solved limit 7466 lbf: about 0.75% / 0.45% differences from the rounded trial. The source also prints 10590 once, inconsistent with its 10950 elsewhere; we retain the correct secant physics. https://engineeringlibrary.org/reference/simple-column-analysis-air-force-stress-manual
Inputs: Cross-section = Solid round; Outside diameter = 30.861 mm; Unbraced length = 1,270 mm; Enter project material properties = yes; Project elastic modulus = 206.8 GPa; Project yield / compressive strength = 75.498 MPa; Load application = Eccentric · pinned secant formula; Load eccentricity = 0.9644 mm; Applied compression = 33.362 kN; the others as above.
| Result | Source | This calc |
|---|---|---|
| Secant eccentricity ratio | 0.25 | 0.25 |
| Maximum elastic compressive stress at applied load | 75.498 ± 0.8 MPa | 76.066 MPa |
| Estimated limiting load · selected case | 33.362 ± 0.2 kN | 33.211 kN |
AISC W8X24 · catalog geometry and unit conversion
Source: AISC Shapes Database v16.0, W8X24 original record: A=7.08 in², Ix=82.7 in⁴, Iy=18.3 in⁴. Exact inch=25.4 mm converts those independent catalog properties; this is a data-transfer and unit check, not an independent buckling result. Original workbook mirror: https://web.ics.purdue.edu/~jhunjhu0/Steel%20Design/aisc-shapes-database-v16.0.xlsx
Inputs: the default inputs above.
| Result | Source | This calc |
|---|---|---|
| Cross-sectional area | 4,568 mm² | 4,568 mm² |
| Second moment about x | 34,422,339 mm⁴ | 34,422,339 mm⁴ |
| Second moment about y | 7,617,035 mm⁴ | 7,617,035 mm⁴ |
6061-T6 · published extrusion properties
Source: McKechnie Aluminium, Alloy 6061 Revision 6 (April 2023), p.1: compression modulus 69.7 GPa; T6 minimum 0.2% tensile proof strength 240 MPa. The proof strength is used only as a preliminary strength ceiling, not a certified compressive allowable. https://www.mckechnie.co.nz/uploads/PDF/Technical-Specifications/Aluminium-Specifications/6061%20Revision%206.pdf
Inputs: Material preset = Aluminium 6061-T6 extrusion; the others as above.
| Result | Source | This calc |
|---|---|---|
| Elastic modulus | 69,700 MPa | 69,700 MPa |
| Yield / crushing-strength ceiling | 240 MPa | 240 MPa |







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